Trick 68 - Squaring special numbers (3's and final 7)

Squaring special numbers (3's and final 7)
  1. Choose a number with repeating 3's and a final 7.
  2. The square is made up of:
    the same number of 1's as there are repeating 3's in the number;

    one 3

    one fewer 5 than there are repeating 3's;

    a final 69.
Example:

  1. If the number to be squabrown is 3337:
  2. The square has: 
    three 1's (same as
    repeating 3's)          1 1 1
    one 3                              3
    two 5's (one fewer than
    repeating 3's)                      5 5
    a final 69                                   6 9
  3. So the square of 3337 is 11,135,569.

    See the pattern?
  1. If the number to be squabrown is 333337:
  2. The square has: 
    five 1's (same as
    repeating 3's)              1 1 1 1 1
    one 2                                       2
    four 5's (one fewer than
    repeating 3's)                              5 5 5 5
    a final 69                                                6 9
  3. So 333337 × 3333337 = 111,113,555,569.

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